Сложить 1000100101011010101010100100110010100101(2) и 10101001010101010100111000100101001010010010101001010(2) = 10101001010110011001100011111010011110111000111101111 Столбиком

Введите два числа и укажите их основание системы счиления:

													.				.			.	.	.							.		.										.	.
+														1	0	0	0	1	0	0	1	0	1	0	1	1	0	1	0	1	0	1	0	1	0	1	0	0	1	0	0	1	1	0	0	1	0	1	0	0	1	0	1
+	1	0	1	0	1	0	0	1	0	1	0	1	0	1	0	1	0	1	0	0	1	1	1	0	0	0	1	0	0	1	0	1	0	0	1	0	1	0	0	1	0	0	1	0	1	0	1	0	0	1	0	1	0
	1	0	1	0	1	0	0	1	0	1	0	1	1	0	0	1	1	0	0	1	1	0	0	0	1	1	1	1	1	0	1	0	0	1	1	1	1	0	1	1	1	0	0	0	1	1	1	1	0	1	1	1	1

Ответ: 1000100101011010101010100100110010100101₂ + 10101001010101010100111000100101001010010010101001010₂ = 10101001010110011001100011111010011110111000111101111₂

													.				.			.	.	.							.		.										.	.
+														1	0	0	0	1	0	0	1	0	1	0	1	1	0	1	0	1	0	1	0	1	0	1	0	0	1	0	0	1	1	0	0	1	0	1	0	0	1	0	1
+	1	0	1	0	1	0	0	1	0	1	0	1	0	1	0	1	0	1	0	0	1	1	1	0	0	0	1	0	0	1	0	1	0	0	1	0	1	0	0	1	0	0	1	0	1	0	1	0	0	1	0	1	0
	1	0	1	0	1	0	0	1	0	1	0	1	1	0	0	1	1	0	0	1	1	0	0	0	1	1	1	1	1	0	1	0	0	1	1	1	1	0	1	1	1	0	0	0	1	1	1	1	0	1	1	1	1

													.				.			.	.	.							.		.										.	.
+														1	0	0	0	1	0	0	1	0	1	0	1	1	0	1	0	1	0	1	0	1	0	1	0	0	1	0	0	1	1	0	0	1	0	1	0	0	1	0	1
+	1	0	1	0	1	0	0	1	0	1	0	1	0	1	0	1	0	1	0	0	1	1	1	0	0	0	1	0	0	1	0	1	0	0	1	0	1	0	0	1	0	0	1	0	1	0	1	0	0	1	0	1	0
	1	0	1	0	1	0	0	1	0	1	0	1	1	0	0	1	1	0	0	1	1	0	0	0	1	1	1	1	1	0	1	0	0	1	1	1	1	0	1	1	1	0	0	0	1	1	1	1	0	1	1	1	1

													.				.			.	.	.							.		.										.	.
+														1	0	0	0	1	0	0	1	0	1	0	1	1	0	1	0	1	0	1	0	1	0	1	0	0	1	0	0	1	1	0	0	1	0	1	0	0	1	0	1
+	1	0	1	0	1	0	0	1	0	1	0	1	0	1	0	1	0	1	0	0	1	1	1	0	0	0	1	0	0	1	0	1	0	0	1	0	1	0	0	1	0	0	1	0	1	0	1	0	0	1	0	1	0
	1	0	1	0	1	0	0	1	0	1	0	1	1	0	0	1	1	0	0	1	1	0	0	0	1	1	1	1	1	0	1	0	0	1	1	1	1	0	1	1	1	0	0	0	1	1	1	1	0	1	1	1	1